6/y-3-2/y=7y+3/y^2-9

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Solution for 6/y-3-2/y=7y+3/y^2-9 equation:


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

6/y-(2/y)-3 = 7*y+3/(y^2)-9 // - 7*y+3/(y^2)-9

6/y-(7*y)-(2/y)-(3/(y^2))-3+9 = 0

6/y-7*y-2*y^-1-3*y^-2-3+9 = 0

4*y^-1-7*y^1-3*y^-2+6*y^0 = 0

(6*y^2-7*y^3+4*y^1-3*y^0)/(y^2) = 0 // * y^4

y^2*(6*y^2-7*y^3+4*y^1-3*y^0) = 0

y^2

6*y^2-7*y^3+4*y-3 = 0

{ 1, -1, 3, -3 }

1

y = 1

6*y^2-7*y^3+4*y-3 = 0

1

y-1

3-7*y^2-y

6*y^2-7*y^3+4*y-3

y-1

7*y^3-7*y^2

4*y-y^2-3

y^2-y

3*y-3

3-3*y

0

3-7*y^2-y = 0

DELTA = (-1)^2-(-7*3*4)

DELTA = 85

DELTA > 0

y = (85^(1/2)+1)/(-7*2) or y = (1-85^(1/2))/(-7*2)

y = (85^(1/2)+1)/(-14) or y = (1-85^(1/2))/(-14)

y in { (85^(1/2)+1)/(-14), (1-85^(1/2))/(-14), 1}

y in { (85^(1/2)+1)/(-14), (1-85^(1/2))/(-14), 1 }

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